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2young2care
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Joined: 09 Jul 2004
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 Posted: Sat Jun 03, 2006 1:54 pm Post subject: |
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in retaliation to Ö...
heres whatcha gotta do:
1 - center your head on the screen like a foot away...
2 - close your left eye
3 - stare at the ball with your right eye
4 - on your peripheral vision see what happens to the cross
http://www.wbreim.com/bs/Blindspot.swf
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| Posted: Sat Jun 03, 2006 1:54 pm Post subject: Advertisement |
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[TN] Nathan
ALMIGHTY PWNER!
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mojo1340
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Joined: 19 Jun 2004
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| Posted: Sat Jun 03, 2006 10:49 pm Post subject: |
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| ^^^^ Is that guy ordering Chinese food? |
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fussnfeathers
Lord of the Tweak
Joined: 14 Dec 2004
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| Posted: Sat Jun 03, 2006 11:27 pm Post subject: |
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| 2young2care wrote: | in retaliation to Ö...
heres whatcha gotta do:
1 - center your head on the screen like a foot away...
2 - close your left eye
3 - stare at the ball with your right eye
4 - on your peripheral vision see what happens to the cross
http://www.wbreim.com/bs/Blindspot.swf
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Doesn't work for me. I'm blind in my right eye. 
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Rocksteady
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Joined: 20 Aug 2004
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| Posted: Sat Jun 03, 2006 11:41 pm Post subject: |
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Funny in a weird way,
how does this work???? 
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Rocksteady
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Joined: 20 Aug 2004
Posts: 1190
Location: location, location!
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| Posted: Sat Jun 03, 2006 11:44 pm Post subject: |
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| fussnfeathers wrote: | | 2young2care wrote: | in retaliation to Ö...
heres whatcha gotta do:
1 - center your head on the screen like a foot away...
2 - close your left eye
3 - stare at the ball with your right eye
4 - on your peripheral vision see what happens to the cross
http://www.wbreim.com/bs/Blindspot.swf
|
Doesn't work for me. I'm blind in my right eye. |
FnF, sorry about your eye, what happened? 
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2young2care
UberTweaker
Joined: 09 Jul 2004
Posts: 1031
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| Posted: Sun Jun 04, 2006 2:28 am Post subject: |
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| Rocksteady wrote: | Funny in a weird way,
how does this work????
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because the triangles aren't congruent. check the slope of the "hypotonuse" of all three triangles. you get 2/5, 3/8, and for the big "triangle" it would be 5/13. we'er assuming right angles, so the big "triangle" is a quadralateral, because the two smaller triangles don't have the same angle measures.
illustrated:
god bless trig... 
and to think, our clas had to spend 3 weeks learning to do this. even though "we" learned it last year.
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Je suis trop jeun de m'inquiéter. |
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sickofsoyo
Tweakafile
Joined: 23 Apr 2005
Posts: 644
Location: NJ... yup
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| Posted: Sun Jun 04, 2006 9:00 am Post subject: |
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well 2y... if you were to use the pythagorean theorem a^2 +b^2=C^2... each triangle is congruent to each other, and it you find the area of each shape, that is congruent... You can also find the tangent, cosign, and sign of each using the sides, the angles of the triangle are congruent... so where does the whole come from? because you switch the red and green triangles, to keep the same form, the grren and yellow boxes are pushed down, causing them to not fit correctly... (I'm taking geometry honors, but I suck at it so correct me if Im wrong)
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Xal
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Joined: 15 Jul 2004
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| Posted: Sun Jun 04, 2006 12:52 pm Post subject: |
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I have seen this before and it irritated me then too 
Anyone feel like figuring out the areas of each shape and then comparing the total areas of each construct? I can't be bothered 
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2young2care
UberTweaker
Joined: 09 Jul 2004
Posts: 1031
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| Posted: Sun Jun 04, 2006 2:14 pm Post subject: |
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| sickofsoyo wrote: | | well 2y... if you were to use the pythagorean theorem a^2 +b^2=C^2... each triangle is congruent to each other, and it you find the area of each shape, that is congruent... You can also find the tangent, cosign, and sign of each using the sides, the angles of the triangle are congruent... so where does the whole come from? because you switch the red and green triangles, to keep the same form, the grren and yellow boxes are pushed down, causing them to not fit correctly... (I'm taking geometry honors, but I suck at it so correct me if Im wrong) |
uhhhh yeah. not congruent similar but i knowwhat you mean, and they're not.
first of all, i used co-tangents to find the angles, tan^-1 2/5=21.801, tan^-1 3/8=20.556, use the "no choice" theorem to find the other angles.
OMFG i'm an idiot.. i need to change that piccy (i did this at like 4AM) the other angles should be: (green triangle) 68.199° (red triangle) 69.444°. anyway, the point is that they're not similar by AAA.
also, for ratios of the sides, 2/3, 5/8, and 29^(1/2)/79^(1/2) are obviosly not equal, thus they are not similar by SSS.
Idk what material is included in your geometry classes, but you should know how to do that. i do understand your brain turning off over summer 
or it could be MY mind that's turned off. (Ö would say it was never on...)
i'll re-do that image so that it's right. i'll include side lengths so you can understand better if you're having trouble
| Xal wrote: | I have seen this before and it irritated me then too
Anyone feel like figuring out the areas of each shape and then comparing the total areas of each construct? I can't be bothered |
i did last night. the red triangle=12, green triangle=5, orange thing=7, lime green thing=8. 12+5+7+8=32
if the top triange were a real triangle, it would be 32.5
if the bottom were a real triangle were an actual triangle with a square hole in it, it'd be 31.5 
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sickofsoyo
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Joined: 23 Apr 2005
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| Posted: Sun Jun 04, 2006 2:45 pm Post subject: |
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gah... we did that stuff in the beginning of the year... we are in 3D shapes and CIRCLES now WOOOOOOOOOO... I hate math... biology is more fun, get to dissect pigs...
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2young2care
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| Posted: Sun Jun 04, 2006 3:09 pm Post subject: |
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i hate to double post (Nathan if you could merge my posts that'd be great. too lazy to re-do my quotes and smilies)
SoS, take the slopes of each of the hypotenuses. red triangle=3/8 green triangle=2/5. close but no cigar. there's an extra vertex where these two lines meet. pick's theorem (a really cool theorem that i found while looking for another theorem i was going to use instead... wiki here)
says that the area of the top quadralateral is 23+20/2-1 = 32
and that the bottom quadralateral (if the hole was filled) (look closely and count your points) is 24+20/2-1 = 33
there's your hole.
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sickofsoyo
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| Posted: Sun Jun 04, 2006 4:20 pm Post subject: |
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ahhh. we didnt learn about that theorem, would have made it easier...
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2young2care
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| Posted: Sun Jun 04, 2006 4:38 pm Post subject: |
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| sickofsoyo wrote: | | ahhh. we didnt learn about that theorem, would have made it easier... |
nor did we. why can't they teach us the useful stuff!?
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sickofsoyo
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| Posted: Sun Jun 04, 2006 5:22 pm Post subject: |
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BAHA.... yeah, if I knew that I wouldnt have failed the tests I did...
ahem getting back on subject... (geometry shouldnt be one)
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Xal
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| Posted: Mon Jun 05, 2006 1:03 am Post subject: |
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| 2young2care wrote: | i hate to double post (Nathan if you could merge my posts that'd be great. too lazy to re-do my quotes and smilies)
SoS, take the slopes of each of the hypotenuses. red triangle=3/8 green triangle=2/5. close but no cigar. there's an extra vertex where these two lines meet. pick's theorem (a really cool theorem that i found while looking for another theorem i was going to use instead... wiki here)
says that the area of the top quadralateral is 23+20/2-1 = 32
and that the bottom quadralateral (if the hole was filled) (look closely and count your points) is 24+20/2-1 = 33
there's your hole. |
Thats what I thought I never did all that well at math but Physics, that was my favorite and rule one, matter can not be created or destroyed, just displaced Common sense really Actually I first saw a similar pic in an IQ test I took a few years back.
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2young2care
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| Posted: Mon Jun 05, 2006 3:14 am Post subject: |
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it can't be created or destroyed, but it can be converted into energy. what's to say i didn't just make tht up and the real answer is "it exploded" ?
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2young2care
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| Posted: Mon Jun 05, 2006 5:47 am Post subject: |
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ok, not really a "picture"....
still hillarious tho...
http://youtube.com/watch?v=CLxMN5YMS3A
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ToggleHead
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| Posted: Mon Jun 05, 2006 9:51 am Post subject: |
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HA HA HA HA
...math humor....
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2young2care
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| Posted: Mon Jun 05, 2006 3:56 pm Post subject: |
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but it does pose the question: if zero devided by anything is zero, any number over itself is one, and you can't divide by zero, what's zero devided by zero?
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fussnfeathers
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| Posted: Mon Jun 05, 2006 4:11 pm Post subject: |
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zero divided by zero equals a peanut butter sandwich. Because ice cream doesn't have bomes, of course.
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sickofsoyo
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| Posted: Mon Jun 05, 2006 4:21 pm Post subject: |
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hmmm thats a good question... 0 divided by zero... according to the computer, it is (result of function is undefined)...
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2young2care
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| Posted: Mon Jun 05, 2006 6:08 pm Post subject: |
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ok, i had an idea.
set 0/0 equal to x, x=0/0
then multiply both sides by 0, you get 0x=0.
so x=all real numbers, because any number multiplied by 0 is equal to zero.
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Zero_Fresh
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| Posted: Tue Jun 06, 2006 9:46 am Post subject: |
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Yeah, or it could be just zero.
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ToggleHead
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Joined: 03 Mar 2004
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| Posted: Tue Jun 06, 2006 10:06 am Post subject: |
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actually....its one of our own forum members names....
null set
since zero is actually an integer, but only represents the absence of of any logical denomination, its like trying to have a vampire bite a unicorn.....
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